Mean of DPD
EXAMPLE
Let's use the same experiment/random variable as in the previous example, namely the number of heads one observes after flipping two coins. Recall we have the following table for our discrete probability distribution
|
Outcome \(X\) |
Probability \(P(X)\) |
| 0 | 0.25 |
| 1 | 0.50 |
| 2 | 0.25 |
To calculate the mean we need only multiply each outcome \(X\) with it's corresponding probability \(P(X)\) then sum all of these values.
First we multiply
| \(X\cdot P(X)\) |
| \(0\cdot 0.25=0\) |
| \(1\cdot 0.50=0.50\) |
| \(2\cdot 0.25=0.50\) |
Now we sum all these
\[0+0.50+0.50=1\]
That is the average number of heads we observe is 1.